Math, asked by varadjrane2597, 1 year ago

Find the zeroes of 2x^2-x-10

Answers

Answered by Anonymous

Solution :

The given polynomial :

f(x) = 2x² - x - 10

2x² +4x-5x -10 = 0

2x(x+2)-5(x+2) = 0

(2x-5)(x+2) = 0

So, Zeros of Polynomial ;

f(x) = 2x - 5

2x - 5 = 0

x = 5/2

Other Zero of Polynomial:

f(x) = x+2

x+2 = 0

x = - 2

Answered by abdul9838

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$\huge \: hola \\ \\ hey \: dude \: here \: is \: ans \\ \\ Question \\ \\ \underline{Find \: the \: Zeros???} \\ \\ \huge \: Answer \\ \\ given \: that\\ \\ \bf \: 2 {x}^{2} - x - 10 = 0 \\ \\ Step \: by \: step \: explaination \\ \\ \bf \: as \: we \: know \: that \\ \\ \bf \: sum \: of \: zeros = - \frac{b(where \: b \: cofficient \: of \: x)}{a(where \: a \: cofficient \: of \: {x}^{2} ) } \\ \\ \bf \: sum \: of \: zeros = - \frac{( - 1)}{2} \\ \\ \bf \: sum \: of \: zeros = \frac{1}{2} \\ \\ \bf \: product \: of \: zeros = \frac{c(where \: c \: constant \: term)}{a(cofficient \: of \: {x}^{2} )} \\ \\ \bf \: product \: of \: zeros\: = - \frac{10}{2} \\ \\ \bf \: product \: of \: zeros = - 5$

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