Math, asked by rishavrishu64, 11 months ago

Find the zeroes of 2x^3-7x^2+3x+16=

Answers

Answered by aneekanara

0

Explanation

6x - 14x +16=0

-8x =-16

-x=-16/8

-×= -2

there fore x = 2

Answer

2

Answered by diwakar99899

0

2*3-7*2+3=2
Zeroes of this answer

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