find the zeroes of 2x square + 7/2 x + 3/4 and verify the relationship between the zeroes and the polynomials
Answers
Answer:
these is the answer which is given above
Given:
2x² + 7/2 x + 3/4
To Find:
Find the zeroes and verify the relationship between the zeroes and the polynomials
Solution:
2x² + 7/2 x + 3/4 = 0
8x² + 14x + 3 = 0 ( Taking L.C.M)
8x² + 12x+2x + 3 = 0
4x(2x+3) + 1(2x+3) =0 ( Taking 4x common)
(4x+1) (2x+3) =0
Now,
4x+1 = 0
= -1/4
(2x+3) = 0
= -3/2
So, the two roots of the equation are -1/4 and -3/2
Now we will verify the zeroes and the polynomial
As we know,
Sum of zeroes of a polynomial = -b/a
Product of zeroes of a polynomial= c/a
where a = coefficient of x²
b = coefficient of x
c = constant term
Sum of zeroes = +
+ = -b/a
-1/4+(-3/2) = -14/8
- 7/2 = -7/2
L.H.S = R.H.S
Product of zeroes =
= c/a
(-1/4)(-3/2) = 3/8
3/8 = 3/8
L.H.S = R.H.S
Hence the zeroes of the polynomial are -1/4 and -3/2. The relationship between the zeroes and the polynomials is verified.