find the zeroes of 2x square - 9 - 3x. verify the relationsp between the zeroes and coefficients
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Hello friend your answer is
2x²-3x-9
2x²+6x-3x-9
2x(x+3) -3(x+3)
(2x-3) (x+3)=0
x=3/2. or -3
then sum of zeroes =-b/a
3/2-3=3/2
and product of zeroes = c/a
-9/2
3/2×-3=-9/2
2x²-3x-9
2x²+6x-3x-9
2x(x+3) -3(x+3)
(2x-3) (x+3)=0
x=3/2. or -3
then sum of zeroes =-b/a
3/2-3=3/2
and product of zeroes = c/a
-9/2
3/2×-3=-9/2
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