Math, asked by vishwarajsingh2141, 20 hours ago

Find the zeroes of 2x3- 11x2 + 17x - 6.

Answers

Answered by mehak2018
0

Answer:

2,1 or 2,3

Step-by-step explanation:

2x³ - 11x² + 17x - 6 = 0

for x = 2 ; value of the equation is zero

(x - 2)(2x² - 7x + 3) = 0

(x - 2)(2x² - 6x - x +3) = 0

(x - 2){2x(x - 3) -1(x - 3)} = 0

(x - 2)(2x - 1)(x - 3) = 0

x = 2,1/2,3

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