find the zeroes of 2xcube+xsquare-6x-3 if two of its zeroes are -(-root 3 and root 3
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Sivashankari:
need to find one more zero
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here is your answer mate
we can write the roots like this...
(x-root 3)(x+ root 3)=x^2 - 3
therefore x^2 - 3 is a perfect root of equation 2x^3+x^2-6x-3
there fore by dividing we get ---- 2x+1
therefore x= -1/2 answer..
.divide is in picture..
please mark it as brainliest
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