Question

find the zeroes of 3x^2-1​

Answer 1

Answer:

3x^2-1

=3x^2=1

= x^2=1/3

$x = \sqrt{1 \div 3}$

Answer 2

Question:-

Find the zeros of 3x²-1

Solution:-

$\sf 3x^{2}-1=0$

$\sf \implies 3x^{2}=1$

$\sf \implies x^{2}=\frac{1}{3}$

$\sf \implies x=\pm \sqrt{\frac{1}{3}}$

Hence, the required answer is $\pm \sqrt{\frac{1}{3}}$