Question

find the zeroes of √3x^2 +10x +7√3

Answer 1

$\sqrt{3} x^{2} + 10x + 7 \sqrt{3} \\ =\sqrt{3} x^{2} + 3x + 7x +7 \sqrt{3} \\ = \sqrt{3} x^{2} + \sqrt{3} \sqrt{3} x + 7x +7 \sqrt{3} \\ = \sqrt{3}x(x+ \sqrt{3} ) +7 (x + \sqrt{3} ) \\= ( \sqrt{3} x + 7)(x + \sqrt{3})$

Answer 2

Answer:

The zeros are $x=-\frac{7}{\sqrt {3}},-\sqrt {3}$    

Step-by-step explanation:

Given : Expression $\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }$

To find : The zeros of the expression?

Solution :

Quadratic expression $\sqrt { 3 } x ^ { 2 } + 10 x + 7 \sqrt { 3 }=0$

We solve the quadratic by splitting middle term split,

$=\sqrt { 3 } x ^ { 2 } + 3 x + 7 x + 7 \sqrt { 3 }$

$=\sqrt { 3 } x ( x + \sqrt { 3 } ) + 7 ( x + \sqrt { 3 } ) }$

$=(\sqrt {3}x+7)(x+\sqrt {3})$

Therefore, The zeros are $x=-\frac{7}{\sqrt {3}},-\sqrt {3}$