Find the zeroes of 3x^2-2
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Answered by
11
Heya......!!!!
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Given equation :- 3x^2 - 2 = 0
=> 3x^2 = 2
=> x^2 = 2/3
=> x = ± √2/√3
Rationalize the Denominator .
=> x = ± √2×√3 / √3×√3
=> x = ± √6/3
=> ➡ Roots of equations are =>> ( + √6/3 ,, - √6/3 )
________________________
Hope It Helps You ^_^
______________________________
Given equation :- 3x^2 - 2 = 0
=> 3x^2 = 2
=> x^2 = 2/3
=> x = ± √2/√3
Rationalize the Denominator .
=> x = ± √2×√3 / √3×√3
=> x = ± √6/3
=> ➡ Roots of equations are =>> ( + √6/3 ,, - √6/3 )
________________________
Hope It Helps You ^_^
Answered by
5
Heya ur answer...
3x^2-2=0
3x^2=2
x^2=2/3
x= +-root 2/3....
3x^2-2=0
3x^2=2
x^2=2/3
x= +-root 2/3....
rohit710:
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