find the zeroes of 3x^2 + 7x + 2 and verify the relation between zero and coefficient
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Step-by-step explanation:
3x² + 7x + 2 = 0
3x² + 6x + x + 2 = 0
3x(x + 2) + 1(x + 2) = 0
(x + 2)(3x + 1) = 0
Zeroes are -2 & -⅓
α = -2, β = -⅓
a = 3, b = 7, c = 2
α + β = -2 + (-⅓) = -2 - ⅓ = -7/3
and α + β = -b/a = -7/3
αβ = (-2)(-⅓) = ⅔
and αβ = c/a = ⅔
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