Question

Find the zeroes of 3x^2_x_4

Answer 1

Answer:

x = - 1 or  $\large x=\dfrac{4}{3}$

Step-by-step explanation:

Given :

$\large p(x)=3x^2-x-4$

We have to find zeroes of p ( x )

By splitting mid term method we get

$\large p(x)=3x^2-x-4\\\\\\\large p(x)=3x^2-4x+3x-4\\\\\\\large p(x)=x(3x-4)+(3x-4)\\\\\\\large p(x)=(3x-4)(x+1)$

For zeroes of p ( x )

x + 1 = 0

x = - 1

or

3 x - 4 = 0

3 x = 4

$x = \dfrac{4}{3}$

Thus we get two zeroes x = - 1 or $\large x=\dfrac{4}{3}$

Answer 2

3x² - x - 4

________ [GIVEN POLYNOMIAL]

• We have to find the zeros the polynomial 3x² - x - 4

_______________________________

=> 3x² - x - 4 = 0

=> 3x² + 3x - 4x - 4 = 0

=> 3x (x + 1) - 4 (x + 1) = 0

=> (3x - 4) (x + 1) = 0

• 3x - 4 = 0

=> 3x = 4

=> x = $\dfrac{4}{3}$

• x + 1 = 0

=> x = -1

____________________________

$\dfrac{4}{3}$ and - 1 are the zeros of the polynomial 3x² - x - 4

___________ [ANSWER]