Question

Find the zeroes of √3x² +10x + 7√3​

Answer 1

Answer:

√3x^2+7x+3x+7√3

x(√3x+7)+√3(√3x+7)

(x+√3)(√3x+7)

either x+√3=0

x=-√3

or √3x+7=0

x=-7/√3

Answer 2

Answer:

-7√3 /3 and -√3

Step-by-step explanation:

√3x² +10x + 7√3 =0

√3x² + 3x + 7x + 7√3 =0

√3x(x + √3) +7(x+√3) = 0

(√3x+7) (x+√3) =0

x = -7/√3

= -7√3 /3 ( rationalization)

x = -√3