Question

Find the zeroes of √3x²+10x+7√3 and verify the relationship between the zeroes and its coefficient.
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Answer 1

Answer:

p(x) = √3x2+10x+7√3

= √3x+3x+7x+7√3

= (√3x+7)(x+√3)

= √3x+7 = 0 and x+√3 = 0

= x = -7/√3 and x = -√3

verification by α and β,

let α = -7/√3 and β = -√3

sum of zeros = α+β = -7/√3+(-√3)

= -7/√3-√3

= -7-3/√3

= -10/√3

product of zeroes = αβ

= -7/√3 . -√3

= 7.

verification by coefficients,

sum of zeros = -b/a

= -10/√3.

product of zeros ,

= c/a

= 7√3/√3

= 7.

hence relationship is verified.

Step-by-step explanation:

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