Find the zeroes of 3x2+x-4
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6
3x² + x - 4 = 0
3x²+4x-3x-4= 0
3x(x-1) +4(x-1) = 0
(3x+4)(x-1) =0
x = 1 or -4/3
Hope it helps you...
Answered by
2
Answer:
Therefore , Zeros of p(x) are 1 and 4/3
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