find the zeroes of 4√5x^2-24x-9√5 and verify the relationship between the zeroes and coefficients of the polynomial?
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Step-by-step explanation:
4√3 x² + 5x - 2√3
x= -5 ± √25+96
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8√3
-5± 11
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8√3
-5+11. -5-11
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8√3. 8√3
3 / 4√3. , -2 / √3
let roots be alpha, beta
alpha+beta = -b/a
from eq. -5 / 4√3
3 /4√3 + (-2 / √3)
3 - 8 / 4√3. = -5/4√3
alpha x beta from eq. - 1/2
3/4√3 x -2/√3
-6/12 = -1/2
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