Question

Find the zeroes of 4u+8u^2

Answer 1

zeros of this equation are
0, -1/2

Answer 2

4u+8$u^{2}$

8$u^{2}$ + 4u

Let,

8$u^{2}$ + 4u = 0

4u ( 2u + 1) = 0

u = 0 and u = -1/2