Question

Find the zeroes of 4x^2-5 and verify the relationship between the zeroes and it's coefficients

Answer 1

Answer:

let,

let,p(x) =4x^2-5

let,p(x) =4x^2-5 =4x^2 = 5

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4 =x = √5/√4

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4 =x = √5/√4 = x = √5/2 , -√5/2

Thus, √5/4 , -√5/4 are the zeros of the given polynomial

Answer 2

Answer:

Step-by-step eAnswer:

let,

let,p(x) =4x^2-5

let,p(x) =4x^2-5 =4x^2 = 5

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4 =x = √5/√4

let,p(x) =4x^2-5 =4x^2 = 5 =x^2 = 5/4 =x = √5/√4 = x = √5/2 , -√5/2

Thus, √5/4 , -√5/4 are the zeros of the given polynomialxplanation: