Question

find the zeroes of 4x^2-7 and verify the relationship between the zeroes and it's coefficient

Answer 1

HEY DEAR ... ✌

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Let f(x) = 4x2 - 7

4x2 - 7 = 0

(2x)2 - (√7)2 =

Using a2 - b2 = (a - b)(a + b), we have

(2x - √7)(2x + √7) = 0

2x - √7 = 0 or 2x + √7 = 0

2x = √7 or 2x = -√7

x = √7/2 or x = -√7/2

α + β = √7/2 + (-√7/2) = 0 = 0/4 = -b/a

αβ = √7/2*-√7/2 = -7/4 = c/a

So, α + β = -b/a and αβ = c/a

HOPE , IT HELPS ... ✌

Answer 2

the zeroes of 4x²- 7 are ±√7/2

the sum of zeroes is -√7/2 + √7/2
=0
= - b /a

product of zeroes is (-√7/2)(√7/2)
= -7/4
= c/a

here go ur answer

I hope it helps you

plz brainliest