find the zeroes of 4x^2-7 and verify the relationship betweenthe zeroes and its coefficent
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4x2 - 7 = 0
4x2 = 7
x2 = 7/4
x = +-√7/2
now, a = 4
b = 0
c = -7
α + β = -b/a
√7/2 + (-√7/2) = -0/4
0 = 0
αβ = c/a
√7/2(-√7/2) = -7/4
-7/4 = -7/4
Hence verified
4x2 = 7
x2 = 7/4
x = +-√7/2
now, a = 4
b = 0
c = -7
α + β = -b/a
√7/2 + (-√7/2) = -0/4
0 = 0
αβ = c/a
√7/2(-√7/2) = -7/4
-7/4 = -7/4
Hence verified
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