Question

find the zeroes of : 4x2-4x+1​

Answer 1

Answer:

1/2 and 1/2

Step-by-step explanation:

4x²-4x+1 = 0

4x²-2x-2x +1 = 0

2x(2x-1)-1(2x-1) = 0

(2x-1)(2x-1) = 0

x= 1/2 and 1/2

Answer 2

Answer:

$\huge\boxed{ \underline{ \bf{ \pink{answer}}}}$

Step-by-step explanation:

$\large \orange{ \sf \bold{p(x) = 4 {x}^{2} - 4x + 1}} \\ \large \orange{ \sf \bold{let \: p(x) = 0}} \\ \large \orange{ \sf \bold{ \implies4 {x}^{2} - 4x + 1 = 0}} \\ \large \orange{ \sf \bold{ \implies4 {x}^{2} - (2 + 2)x + 1 = 0}} \\ \large \orange{ \sf \bold{ \implies4 {x}^{2} - 2x - 2x + 1 = 0}} \\ \large \orange{ \sf \bold{ \implies2x(2x - 1) - 1(2x - 1) = 0}} \\ \large \orange{ \sf \bold{ \implies(2x - 1)(2x - 1) = 0}} \\ \large \orange{ \sf \bold{ \implies2x - 1 = 0 \: \: \: \: \: \: \: \: \: \: 2x - 1 = 0}} \\ \large \orange{ \sf \bold{ \implies \: x = \frac{1}{2} \: \: \: \: \: \: \: \: \: \: x = \frac{1}{2}}} \\ \\ \large \red{ \sf \bold{ \therefore \: zero \: of \: p(x) \: is \: is \: \frac{1}{2} }}$