Math, asked by rashu7894, 19 days ago

Find the zeroes of 64 - x ^ 3

pls tell answer I'll mark u as brainlist​

Answers

Answered by soumili1518
0

Answer:

(4)^3-x^3

=(4-x^3+12x(4-x)

Step-by-step explanation:

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Answered by jainmanan815
0

Answer:

x=4

Step-by-step explanation:

x ^{3}  - 64 \\  {x}^{3}  -  {4}^{3 }  \\ x = 4

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