Question

Find the zeroes of 64x2+16x+1 and verify the relationship between the zeroes and it's cofficient

Answer 1

Step-by-step explanation:

to find the zero of a polynomial, equate the polynomial to zero.

64x²+16x+1=0

64x²+8x+8x+1=0

8x(8x+1)+1(8x+1)=0

therefore the zeroes of this polynomial are -1/8;-1/8.