Question

find the zeroes of 6x^2 -3 -7x​

Answer 1

Given equation- 6x²-7x-3

Solution -

6x²-7x-3

6x²-(9-2)x-3

6x²-9x+2x-3

3x(2x-3)+1(2x-3)

(2x-3)(3x+1)

So x= 3/2,-1/3

So zero are 3/2 , -1/3

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Answer 2

ANSWER✔

$\sf\therefore 6x^2-3-7x$

$\sf\implies 6x^2-7x-3=0$

$\sf\implies 6x^2-9x+2x-3=0$

$\sf\implies (3x+1)(2x-3)=0$

$\sf\implies 3x+1=0,2x-3=0$

$\sf\implies 3x=-1,2x=3$

$\sf\implies x= \dfrac{-1}{3}, \: x= \dfrac{3}{2}$

$\sf\implies x= \dfrac{-1}{3},\dfrac{3}{2}$

$\large{\boxed{\bf{ \star\:\: x= \dfrac{-1}{3},\dfrac{3}{2}\:\: \star}}}$

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