Question

find the zeroes of 6x**2-7x-3 and verify the relationship between zeroes and co efficients​

Answer 1

Step-by-step explanation:

6x^2-7x-3

6x^2-9x+2x-3

3x(2x-3)+1(2x-3) =0

(2x-3)(3x+1)=0

2x-3=0 3x+1=0

x=3/2. x= -1/3

relation

sum of roots =3/2-1/3 =7/6=we can understand by equation it is equal to -b/a

product of roots=3/2(-1/3)= -3/6= -1/2 = by equation = c/a