Question

find the zeroes of 6x^2-7x-3 and verify the relationship between the zeroes and the coefficients
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Answer 1

Answer:

It's coefficient is 2

Step-by-step explanation:

Their is no zero

Answer 2

Answer:

Given equation,

                 6$x^{2}$ - 7x - 3 = 0

                 6$x^{2}$ - 9x +2x - 3 = 0                 (solving using factorising method)

                 3x (2x - 3) + 1 (2x - 3) = 0

                 (2x - 3) (3x+1) = 0

                 x = 3/2 , -1/3

Zeros(roots) of given equation are 3/2 and -1/3

=> Sum of zeros is -coefficient of x / coefficient of $x^{2}$ = 7/6

          zeros are 3/2 and -1/3 sum is 3/2 + (-1/3)

                                               = 7/6

=> Product of zeros is constant / coefficient of $x^{2}$ =  -3/6 = -1/2

           zeros are 3/2 and -1/3 product is 3/2 * (-1/3)

                                               = -1/2