find the zeroes of 6x-3-7x
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Step-by-step explanation:
f(x) = 6x2 – 7x – 3
To find the zeros
Let us put f(x) = 0
⇒ 6x2 – 7x – 3 = 0
⇒ 6x2 – 9x + 2x – 3 = 0
⇒ 3x(2x – 3) + 1(2x – 3) = 0
⇒ (2x – 3)(3x + 1) = 0
⇒ 2x – 3 = 0
x = 3/2
⇒ 3x + 1 = 0
⇒ x = -1/3
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