Question

Find the zeroes of :- 6x2-11 root3x+6​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge{\underline{\underline{\bf{ SoLuTiOn\: - }}}}♡$

$Given: 3 x 2 − 2√6x + 2 = 0$

$3 x 2 − √6x − √6x + 2 = 0, √3x ( 3x − 2 ) − 2(√3x − √2 )= 0$

$∴√3x = √2 = 0 \: or \: √3x. \: = √ \frac{2}{3} or \: x \: = √ \frac{2}{3}$

$3x−√2)(√3x−√2)=0∴√3x−√2=0 or √3x−√2=0$

$∴√3x=2 or √3x=2,x=32 or x=32$

$So, the root is repeated twice, \\ one for each repeated factor (√ \frac{3x}{2} )l.$

$∴ The \: two \: equal \: roots \: of$

$3x {}^{2} - 2√6x + 2 = 0 \\ are√ \frac{2}{3} . \: √ \frac{2}{3}$