Math, asked by Anonymous, 1 year ago

find the zeroes of 6x2-3-7x and verify the relationship between the zeroes and the coefficient

Answers

Answered by zishan174
20
6x^2 - 7x - 3
6x^2 - [ 9 - 2 ] - 3
6x^2 - 9x + 2x - 3
3x [ 2x - 3 ] + 1 [ 2x - 3]

( 3x + 1) ( 2x - 3)
3x + 1 2x - 3
x = -1/3 x = 3/2

sum of zeroes b/a
= 7/6

product of zeros c/a
= -3/6 = -1/2


hope this helps
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