Question

Find the zeroes of 6x2 -x-1 and verify the relationship between the zeroes and the coefficients of the poynomial​

Answer 1

Answer :

ATQ 6X²-X-1

spilliting middle term

6x²+3x-2x-1

3x(2x-1)-1(2x-1)

(3x-1) (2x-1)

then,

value of zeroes

3x-1 = 1/3 , 2x-1 = 1/2

• sum of zero = cofficient of x cofficient of x²

1/3 + 1/2 = 1/6

1/6 = 1/6

• product of zero = constant term/cofficient of x²

1/3 * 1/2 = 1/6

1/6 = 1/6

1/3 and 1/2

Answer 2

Answer:

Hello Users, It's answer is -1/3,1/2

Step-by-step explanation: