find the zeroes of 7x^2-11/3y-2/3
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Answer:
-1/7 and 2/3
Step-by-step explanation:
The general form of quadratic equation is
ax² + b x+ c = 0
7x²-11/3x-2/3 = 0
21x²-11x-2 = 0
21x²-14x+3x-2=0
7x(3x-2)+1(3x-2) = 0
(7x+1)(3x-2)=0
x=-1/7 and 2/3
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