Math, asked by sanjusrini, 10 months ago

find the zeroes of 7x^2-11/3y-2/3​

Answers

Answered by awasthiayush004
0

Answer:

-1/7 and 2/3

Step-by-step explanation:

The general form of quadratic equation is

ax² + b x+ c = 0

7x²-11/3x-2/3 = 0

21x²-11x-2 = 0

21x²-14x+3x-2=0

7x(3x-2)+1(3x-2) = 0

(7x+1)(3x-2)=0

x=-1/7 and 2/3

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