Question

find the zeroes of 9t square -6t +1 and verify the relation between zeroes and coefficients.

Answer 1

9tsquare-6t+1

9tsquare-3t-3t+1
3t(3t-1)-1(3t-1)
(3t-1) (3t-1)
3t-1=0
3t-1=0
t=1/3   t=1/3

let alpha be 1/3 and let beta be 1/3

alpha+beta=-(-6)/9=2/3=-b/a

alpha x beta =  1/3 x 1/3 = 1/9 = c/a

therefore the relationship is verified...