find the zeroes of 9t square -6t +1 and verify the relation between zeroes and coefficients.
Answers
Answered by
2
9tsquare-6t+1
9tsquare-3t-3t+1
3t(3t-1)-1(3t-1)
(3t-1) (3t-1)
3t-1=0
3t-1=0
t=1/3 t=1/3
let alpha be 1/3 and let beta be 1/3
alpha+beta=-(-6)/9=2/3=-b/a
alpha x beta = 1/3 x 1/3 = 1/9 = c/a
therefore the relationship is verified...
9tsquare-3t-3t+1
3t(3t-1)-1(3t-1)
(3t-1) (3t-1)
3t-1=0
3t-1=0
t=1/3 t=1/3
let alpha be 1/3 and let beta be 1/3
alpha+beta=-(-6)/9=2/3=-b/a
alpha x beta = 1/3 x 1/3 = 1/9 = c/a
therefore the relationship is verified...
Similar questions