Question

Find the zeroes of a polynomial
7x² - 12x - 4​

Answer 1

Answer:

The first term is, 7x2 its coefficient is 7 .

The middle term is, -12x its coefficient is -12 .

The last term, "the constant", is -4

Step-1 : Multiply the coefficient of the first term by the constant 7 • -4 = -28

Step-2 : Find two factors of -28 whose sum equals the coefficient of the middle term, which is -12 .

-28 + 1 = -27

-14 + 2 = -12 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -14 and 2

7x2 - 14x + 2x - 4

Step-4 : Add up the first 2 terms, pulling out like factors :

7x • (x-2)

Add up the last 2 terms, pulling out common factors :

2 • (x-2)

Step-5 : Add up the four terms of step 4 :

(7x+2) • (x-2)

Answer 2

Answer:

x= 2 or -2/7...using middle term split