find the zeroes of a polynomial x3+4x2-9x-36=0 if two of its zeroes are equal in magnitude but opposite in sign
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Let the zeroes be a, b, c such that a=-b
relationships between zeroes and co-efficient
1)a+b+c=-4
since a=-b
therefore
c=4
2)abc=36
putting c=4,a=-b
-b^2=9
-b^2=3^2
on equating the squares we get
-b=3
Thus zeroes are 3,-3,4
relationships between zeroes and co-efficient
1)a+b+c=-4
since a=-b
therefore
c=4
2)abc=36
putting c=4,a=-b
-b^2=9
-b^2=3^2
on equating the squares we get
-b=3
Thus zeroes are 3,-3,4
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