Math, asked by Sai1903, 1 month ago

find the zeroes of a quadratic equations p(x)= 7x^2-5x-2​

Answers

Answered by amansharma264
4

EXPLANATION.

Quadratic equation.

⇒ 7x² - 5x - 2 = 0.

As we know that,

Factorizes the equation into middle term splits, we get.

⇒ 7x² - 7x + 2x - 2 = 0.

⇒ 7x(x - 1) + 2(x - 1) = 0.

⇒ (7x + 2)(x - 1) = 0.

⇒ x = -2/7  and  x = 1.

                                                                                                                           

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and different, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal or complex conjugate.

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