find the zeroes of a quadratic equations p(x)= 7x^2-5x-2
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EXPLANATION.
Quadratic equation.
⇒ 7x² - 5x - 2 = 0.
As we know that,
Factorizes the equation into middle term splits, we get.
⇒ 7x² - 7x + 2x - 2 = 0.
⇒ 7x(x - 1) + 2(x - 1) = 0.
⇒ (7x + 2)(x - 1) = 0.
⇒ x = -2/7 and x = 1.
MORE INFORMATION.
Nature of the roots of the quadratic expression.
(1) = Real and different, if b² - 4ac > 0.
(2) = Rational and different, if b² - 4ac is a perfect square.
(3) = Real and equal, if b² - 4ac = 0.
(4) = If D < 0 Roots are imaginary and unequal or complex conjugate.
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