Question

Find the zeroes of a quadratic polynomial 2x2 + 3x - 14 and verify the
relationship between the zeroes and its coefficients.​

Answer 1

Answer:

$ANSWER</p><p></p><p>(i) x2−2x−8</p><p></p><p></p><p>Factorize the equation, we get (x+2)(x−4)</p><p>So, the value of x2−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.</p><p>Therefore, the zeros of x2−2x−8 are -2 and 4.</p><p>Now,</p><p></p><p>⇒Sum of zeroes =−2+4=2=−12=−Coefficient  of  x2Coefficient  of  x</p><p></p><p></p><p>⇒Product of zeros =(−2)×(4)=−8 = 1−8=Coefficient  of  x2Constant  term</p><p></p><p></p><p>(ii) 4s2−4s+1</p><p></p><p>Factorize the equation, we get(2s−1)(2s−1)</p><p>So, the value of 4s2−4s+1 is zero when 2s−1=0,2s−1=0, i.e., when s=21 or s=21.</p><p>Therefore, the zeros of </p><p></p><p>$

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