Question

Find the zeroes of a quadratic polynomial 4root3x^2+5x-2root3

Answer 1

4root3x2 + 5x - 2root3 = 0

4root3x2 + 8x - 3x - 2root3 = 0

4x(root3x + 2) - root3(root3x + 2)

(4x - root3)(root3x + 2)

x = root3 / 4

x= - 2/root3

Answer 2

$4 \sqrt{3} {x}^{2} + 5x - 2 \sqrt{3} \\ 4 \sqrt{3} {x}^{2} + 8x - 3x - 2 \sqrt{3} \\ 4x( \sqrt{3}x + 2) - \sqrt{3} ( \sqrt{3} x + 2) \\ ( \sqrt{3} x + 2)(4x - \sqrt{3} ) \\ x = \frac{ \sqrt{3} }{4} and \: - \frac{2 \sqrt{3} }{3}$