Find the zeroes of a. quadratic polynomial,p(x)=21x sq-3
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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akash92:
pls help in my question
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It's simple.
The zero of a quadratic polynomial gives p(x) = 0
So 21x² - 3 = 0
21x² = 3
x² = 3/21
x² - 1/7 = 0
By applying a² - b² = (a+b)(a - b)
(x - 1/√7)(x + 1/√7) = 0
We get here two equations
x - 1/√7 = 0
x + 1/√7 = 0
So x = 1/√7 or x = - 1/√7
So the required zeroes of the p(x) are 1/√7 and - 1/√7
Hope This Helps You!
The zero of a quadratic polynomial gives p(x) = 0
So 21x² - 3 = 0
21x² = 3
x² = 3/21
x² - 1/7 = 0
By applying a² - b² = (a+b)(a - b)
(x - 1/√7)(x + 1/√7) = 0
We get here two equations
x - 1/√7 = 0
x + 1/√7 = 0
So x = 1/√7 or x = - 1/√7
So the required zeroes of the p(x) are 1/√7 and - 1/√7
Hope This Helps You!
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