Question

find the zeroes of a quadratic polynomial x²+15x-154 and verify the relationships between zeroes and coefficient​

Answer 1

Answer:

x²+15x-154

$= {x}^{2} + 22x - 7x - 154 \\ = x(x + 22) - 7(x + 22) \\ = (x + 22)(x - 7) \\ so \: zeros \:are \: \: x = 7 \: and \: - 22 \\ \\ \\ if \: \alpha \: and \: \beta \: are \: the \: zeros \: then \: the \: relationships \: is \: \\ \alpha + \beta = - 15 \\ \\ \alpha \beta = - 154$

$\huge\mathbb\red{UNDERSTAND\:? }$