Question

find the zeroes of a quadratic polynomial x² -2ax+a² -b²
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Answer 1

Answer:

=> (x²+a²-2ax) - b²

=> (x-a)² - b²

=> (x-a+b)(x-a-b)

zeros is

x-a+b = 0. (or). x-a-b = 0

=> x=a-b. (or). x=a+b

so, the roots are,

a-b , a+b

Answer 2

Refer the picture, hope it helps