find the zeroes of cubic polynomial p(x)=x^3+4x^2-5x
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Answered by
2
Step-by-step explanation:
p(0)=0×3+4×0×2-5×0
0+4×0×3×0
0+0×0
answer is .0
......please give me thanks....
Answered by
1
Answer: x^3+4x^2-5x=0
x(x^2+4x-5)=0
x=0 x^2+4x-5=0
x^2+5x-1x-5=0
x(x+5)-1(x+5)=0
(x+5)(x-1)=0
x=-5 x=1
x=0,1,-5
Step-by-step explanation:
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