Question

Find the zeroes of cubic polynomials (i) – x3 (ii) x^2-x^3 (iii) x^3 – 5x^2 + 6x without drawing
the graph of the polynomial.​

Answer 1

Answer:

(i) - x³

-x³ = 0

x = 0, hence zeros of -x³ is 0

(ii) x² - x³

x² - x³ = 0

x²(1 - x) = 0

x² = 0 or, (1 - x ) = 0.

x = 0 , 1

hence, zeros of x² - x³ are 0 , 1

(iii) x³ - 5x² + 6x

x³ - 5x² + 6x = 0

x(x² - 5x + 6) = 0

x(x - 2)(x - 3) = 0

x = 0, 2, 3

hence, zeros of x³ - 5x² + 6x are 0, 2, 3