Find the zeroes of एक्स स्क्वायर प्लस 5 एक्स प्लस सिक्स
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Answer:
x²+ 5x + 6 = 0
x = -b±√b²-4ac/2a
x = -5 ± √5² - 4(1)6 / 2(1)
x = -5± √25 - 24 /2
x = -5±1/2
x = -5+1/2 x = -5-1/2
x = -4/2 x = -6/2
x = -2 x = -3
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