Question

Find the zeroes of f(x=)6x^2-3

Answer 1

$\red{f(x) = 6 {x}^{2} - 3} \\ \green{ 6 {x}^{2} - 3 = 0} \\ \pink{ 6 {x}^{2} = 3 } \\ \purple{ {x}^{2} = \frac{1}{2} } \\ \orange{x = \frac{1}{ \sqrt{2} } \: and \: - \frac{1}{ \sqrt{2} } }$
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