find the zeroes of following quadratic eq. 2√3x^2-5x+√3
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1
Answer:
Let f(x)=2
3
x
2
−5x+
3
=2
3
x
2
−2x−3x+
3
=2x(
3
x−1)−
3
(
3
x−1)
to find the zeroes, Let f(x)=0
(
3
x−1) or (2x−
3
)=0
x=
3
1
=
3
3
or x=
2
3
x=
3
3
or x=
2
3
Again ,
Sum of zeroes =
3
3
+
2
3
=
6
5
3
=
2
3
5
=
a
−b
=
(coefficient of x
2
)
(−coefficient of x)
Product of zeroes =
3
3
×
2
3
=
6
3
=
2
1
=
a
c
=
coefficient of x
2
Constant term
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