Math, asked by Lunatic583l, 1 month ago

find the zeroes of following quadratic eq. 2√3x^2-5x+√3​

Answers

Answered by nandanipandey9094
1

Answer:

Let f(x)=2

3

x

2

−5x+

3

=2

3

x

2

−2x−3x+

3

=2x(

3

x−1)−

3

(

3

x−1)

to find the zeroes, Let f(x)=0

(

3

x−1) or (2x−

3

)=0

x=

3

1

=

3

3

or x=

2

3

x=

3

3

or x=

2

3

Again ,

Sum of zeroes =

3

3

+

2

3

=

6

5

3

=

2

3

5

=

a

−b

=

(coefficient of x

2

)

(−coefficient of x)

Product of zeroes =

3

3

×

2

3

=

6

3

=

2

1

=

a

c

=

coefficient of x

2

Constant term

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