find the zeroes of following quadratic polynomial and verify the relationship between zeroes and coefficients p(x)=2x^2-3x-9
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Answer:
qn is 2x²-3x-9 isn't it?
Step-by-step explanation: here's your answer
by splitting middle term we can find the zeroes of the given polynomial
product is -18
sum is -3
so we can split the polynomial to:
2x²-6x+3x-9
by putting brackets,
(2x²-6x)+(3x-9)
by taking common,
2x(x-3)+3(x-3)
we can convert it into
(2x+3) & (x-3)
now we can find the zeroes,
by taking one of the equation ,
2x+3=0
2x=-3
x=-3/2
therefore one zero is -3/2
for next zero,
x-3=0
x=3
there fore the the zeroes of the equation 2x²-3x-9 are:
x=-3/2 & x=3
hope it helps for you
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