find the zeroes of k of the given quadratic equation if it has two equal roots.
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2X² + KX + 3 = 0
Here,
A = 2 , B = K and C = 3
Discriminant ( D ) = 0
b² - 4ac = 0
(k)² - 4 × 2 ×3 = 0
k² - 24 = 0
K² = 24
K = √24
K = 2√6
Here,
A = 2 , B = K and C = 3
Discriminant ( D ) = 0
b² - 4ac = 0
(k)² - 4 × 2 ×3 = 0
k² - 24 = 0
K² = 24
K = √24
K = 2√6
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2
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