Question

find the zeroes of n^2-n-6​

Answer 1

therefore zeroes are 3 and -2.

Answer 2

Solution:

The Given Polynomial is

• n²-n-6

Now, Arrange this Polynomial in Quadratic Polynomial i.e ax² + bx + c

let Polynomial be f(x) = n²-n-6

So, Zeroes of Polynomial :

☛ f(x) = n²-n-6

☛ n² - n - 6

☛ n² + 2n - 3n - 6

☛ n(n+2)-3(n+2)

☛ (n+2)(n-3)

Zeros of Polynomial be ;

f(x) = n+2 0r f(x) = n-3

☛ n + 2 = 0. ☛ n - 3 = 0

☛ n = - 2. ☛ n = 3

Therefore, Polynomials are - 2 and 3.