Question

Find the zeroes of p(x) = 2x²– x – 6 and verify the relationship of zeroes with these co-efficients​

Answer 1

Answer:

P(x) = 2x² - x - 6

a + b = -1

a × b = -12

3 - 4 = -1

3 - 4 = -12

2x² - x - 6

= 2x² - 4x + 3x - 6

= 2x(x - 2) + 3(x - 2)

= (2x + 3) (x - 2)

2x + 3 = 0 x = 2

2x = -3

x = -3/2

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Answer 2

Answer:

Step-by-step explanation:

p(x)=2$x^{2}$-x-6

= 2x^2+4x-3x-6

=2x(x+2)  -3(x+2)

= X= 3/2    X= -2

  alpha        beta

sum of zero's = -b/a

3/2+(-2)/1        = -(1)/2

-1/2                 = -1/2   (verified)

Product of zero's = c/a

3/2* (-2)                = 6/2

3                           =  3      (verified)