Question

find the zeroes of p(x) =√2xsquare+7x+5√2 and verify the relationship between zeroes and coefficient​

Answer 1

Answer:

$√2x^2+7x+5√2 =0\\√2x^2+7x+5√2=0\\√2x^2+5x+2x+5√2=0\\x(√2x+5)+√2(√2x+5)=0\\(√2x+5)(x+√2)=0\\x= \frac {-5}{√2}, {-√2}$

Find the relationship by own..xD

Answer 2

➤ 2x2 -7x +5

➤ 2x2 -2x -5x + 5

➤ 2x ( x -1) -5 (x-1)

➤ (2x-5) (x-1)

➤ x = 5/2, 1