Math, asked by smitmakwana1920, 9 months ago

Find the zeroes of P(x) = 3x2 + 5x - 8.

Answers

Answered by Anonymous
2

Answer:

P(x)=3x²+5x-8

ZEROS:-

3x²+5x-8=0

3x²+8x-3x-8=0

3x²-3x+8x-8=0

3x(x-1)8(x-1)=0

(3x+8)(x-1)=0

x-1=0. 3x+8=0.

x=1. ; x=-8/3

Similar questions